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@planet4589 | |||||
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Corrected orbital data for the Roadster: 0.99 x 1.71 AU x 1.1 deg
C3 = 12.0, passes orbit of Mars Jul 2018, aphelion November
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Bob Fritz
@RAFritz7
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7 Feb 18 |
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Really not even close to the asteroid belt. It will make it just past Mars orbit.....right??
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Jonathan McDowell
@planet4589
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7 Feb 18 |
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Correct
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Ben Pearson
@kd7uiy
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7 Feb 18 |
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So these numbers are assuming that the C3=12 was correct? Either the C3 is correct, or the distance from the sun is correct, but not both?
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Scott Sutherland (π¦οΈπ©οΈππππ°οΈ)
@ScottWx_TWN
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7 Feb 18 |
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So, it's more like this corrected plot? pic.twitter.com/qYeFgXNAxT
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Jonathan McDowell
@planet4589
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7 Feb 18 |
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We now know that the C3=12 was correct and the 'aphelion in the belt at 2.6 AU' was a mistake.
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Jonathan McDowell
@planet4589
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7 Feb 18 |
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More or less
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Jim B
@httprover
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7 Feb 18 |
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Was the Earth at the perihelion of the orbit at the time the Roadster left the Earth's orbit? Would the Earth's heliocentric longitude give us a line of apsides?
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Jonathan McDowell
@planet4589
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7 Feb 18 |
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Yes. I have (approximately) i = 1.10, node = 316.78, AOP = 179.33; M = 3.82 at Feb 11 1800 UTC
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Jonathan McDowell
@planet4589
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7 Feb 18 |
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That's to pass Mars slowly . You can get there much quicker if you don't mind whizzing past at high speed, with the same initial energy as if you were doing the slow route
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Jonathan McDowell
@planet4589
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7 Feb 18 |
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It's not going anywhere near Mars. And it's dead now, no ability to manuever
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Gerrit Immink
@gerrit_immink
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7 Feb 18 |
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Do you have any idea of how close roadster will get to mars on this first orbit/when?
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Jonathan McDowell
@planet4589
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7 Feb 18 |
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About 100 million km, not close at all
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I am
@p3rfact
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8 Feb 18 |
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Am Inright in saying there is no equipment on the Roadster thatβs will send us any type of data back and itβs so small, our telescopes or radar etc canβt track it? Itβs just theoretical information now, right? Will Mars orbiter be able to see or detect it when it passes by Mars?
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Dhruva Malekar
@DhruvaMalekar
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8 Feb 18 |
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I want to understand the calculation a lot better ...where should I start....as in what is C3?? And what formula is used etc..
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Joseph Shuster Sr
@iamhondo
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8 Feb 18 |
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"...crosses the orbits of Earth..." According to what I've seen it intersects Earth's orbit. To cross (inside) Earth's orbit, they'd need to slow down a bit (most efficiently at aphelion).
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Dave Faubert
@res_canadensis
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8 Feb 18 |
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You know a lot, so I have a question: Musk advertised the car as being on a Mars-orbit trajectory. After the final burn. he bragged that it was going past that. Isn't this cause for concern? If Cassini went past Saturn no one would be bragging.
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Jonathan McDowell
@planet4589
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8 Feb 18 |
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He was speaking loosely, it was never targeted precisely for Mars. And the going past that brag turned out to be a mistake, it is in fact going just a smidge past Mars orbit
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Jonathan McDowell
@planet4589
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8 Feb 18 |
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Well, it's not quite tangent to Earth orbit, perihelion is very slightly inside
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Jonathan McDowell
@planet4589
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8 Feb 18 |
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search on 'astrodynamics'. We split the problem up into Kepler's-laws-like problems in the near-Earth and far-from-Earth cases. Near Earth it's a hyperbola, and C3 is velocity-squared it would have at infinity if the rest of the universe didn't exist
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