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Keenan Crane
How do you chop up a tetrahedron into nicely-shaped little cubes? Here's one way, obtained a la symmetric moving frames (). How else can you do it?
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Amir Vaxman 30. pro
Odgovor korisniku/ci @keenanisalive @AntoineVacavant
This is effectively a Catmull-Clark subdivision (with some 3D version) to get the parametric domain followed by smaller-cube refinement, btw.
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Keenan Crane 30. pro
Odgovor korisniku/ci @amirvaxman_dgp @AntoineVacavant
Right. Here's a picture of the subdivision is talking about, which can be used to trivially convert any tetrahedral mesh into a hexahedral mesh—but with poor angles near tet vertices. Any other way to split up a tet into cubes? :-)
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angelo 13. sij
Odgovor korisniku/ci @keenanisalive
Nice ! But it is really a pity not to have access to some code to be able to reproduce yours results from Symmetric Moving Frames. Even Matlab code would be great. We are unable to benchmark with other methods.
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Keenan Crane 13. sij
Odgovor korisniku/ci @angelo93728560 @ALoopingIcon
Hi , we’d love to get some example code out. In the meantime you can compare against our results (and many more) at
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Antoine Vacavant's Rising Force 30. pro
Odgovor korisniku/ci @keenanisalive
I have to say that I love this discussion with 3D, drawings and topology 👌
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Jim 30. pro
Odgovor korisniku/ci @keenanisalive @Atrix256
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Carter T Schonwald 1. sij
Odgovor korisniku/ci @keenanisalive @gabrielpeyre
It only works on things which are symmetric though?
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