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John Carlos Baez
A beautiful solution of the gravitational 4-body problem. But keep watching, because it's not stable!
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John Carlos Baez 11. sij
Odgovor korisniku/ci @johncarlosbaez
This solution of the 3-body problem is stable, apparently:
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Venu Madhav Govindu 11. sij
Odgovor korisniku/ci @johncarlosbaez
Assuming its not a numerical issue, I am not sure I understand why symmetry should fall apart.
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John Carlos Baez 11. sij
Odgovor korisniku/ci @venugovindu
If it's not perfectly symmetrical at the start, it can become extremely asymmetric later. Or maybe it's symmetrical at the start but the numerical errors are asymmetric for some reason. In the real world, outside influences can introduce the asymmetry.
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Josh Foster 11. sij
Odgovor korisniku/ci @johncarlosbaez @InertialObservr
I don't understand why it's unstable. I'm the farthest thing from a physicist, so I'm sure I'm missing something obviously, but it seems to me like it should be stable. Is something influencing their movement besides each other?
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John Carlos Baez 11. sij
Odgovor korisniku/ci @JoshuaDFoster1 @InertialObservr
Lots of systems are unstable, and then they can *look* like they're doing something simple, but in reality they're not quite, and the deviation from simple behavior gradually builds up over time and suddenly spirals out of control. Just solve the equations...
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Vitalii Akimov 11. sij
Odgovor korisniku/ci @johncarlosbaez
does this have some nice 4d interpretation like you wrote about 2 body problem?
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John Carlos Baez 11. sij
Odgovor korisniku/ci @vitalii_akimov
I doubt it! The gravitational 2-body problem is very special in having a secret 4-dimensional rotation symmetry.
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Daniele Pinna 12. sij
Odgovor korisniku/ci @johncarlosbaez
How can we say this isn't the result of a numerical rounding error in the integration script breaking the symmetry? Did someone try reproducing this result?
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John Carlos Baez 12. sij
Odgovor korisniku/ci @PestoPoppa
It's either the result of a numerical rounding error, or a deliberately introduced imperfection in the initial conditions. It doesn't really matter much: either way, a slight deviation from symmetry is getting amplified.
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Pedro Larroy 🇺🇳 ∞ 12. sij
Odgovor korisniku/ci @johncarlosbaez
Is the author using floating point for this simulation?
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John Carlos Baez 12. sij
Odgovor korisniku/ci @plarroy @simon_tardivel
I don't know. Are you, ? Either numerical errors or deliberate errors introduced into the initial conditions are being amplified by the instability of this trajectory.
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