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Diego Rattaggi
Mathematician. MTT coin flipper. Wombatologist. What fraction is shaded? Roger Federer H2H
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Diego Rattaggi 11h
Istomin
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Diego Rattaggi 14h
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Diego Rattaggi 22h
Replying to @pickover
... and 10! is the precise number of seconds in 42 days.
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Diego Rattaggi Aug 16
Replying to @RAnForr784
This result looks perfect 😀
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Diego Rattaggi Aug 16
0 0 0 0 0 0 0 0 0 is wrong?
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Diego Rattaggi Aug 16
Answer is 0.
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Diego Rattaggi Aug 16
Replying to @Caner_KMZ
10 ?
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Diego Rattaggi Aug 16
Replying to @RAnForr784
Hmm, seems too far away
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Diego Rattaggi Aug 16
Transforming what I have learnt today into a puzzle.
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Diego Rattaggi Aug 16
Replying to @ilarrosac @andkomi
interesting graph
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Diego Rattaggi Aug 16
Replying to @ilarrosac @andkomi
Very nice for n=12. So rational fractions appear for n=3,4,5,6,12. Is there a chance of any other?
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Ignacio Larrosa Aug 16
Replying to @andkomi @diegorattaggi
👍🏼You can also use the floor(x) = [x] function. I thought that changing the contact vertex/side of the polygons would be difficult to obtain the general formula, but you see that it is not so ... Nice result for n = 12.
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Diego Rattaggi Aug 15
Replying to @maliuhud
but it's not 2A and A ...
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Ignacio Larrosa Aug 15
Replying to @diegorattaggi
From n = 10 I think that the approximation of polygons by circles begins to give good results, although it is still very far from π²/n
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Diego Rattaggi Aug 15
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Diego Rattaggi Aug 15
Replying to @ilarrosac
I got (72-32sqrt(2))/49 for the octagon and 90-40sqrt(5) for the decagon.
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Diego Rattaggi Aug 15
in the middle
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Diego Rattaggi Aug 15
Replying to @ilarrosac
...but somehow surprising, if considering only small n.
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Diego Rattaggi Aug 15
Replying to @ilarrosac
Yes, asymptotically π²/n.
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Diego Rattaggi Aug 15
Replying to @le_becachel
View from the yellow point.
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