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András Kovács 8. lis
Odgovor korisniku/ci @Iceland_jack
Introduction seems a bit off to me. Algebraic models of lambda calculi are known already, including treatment of binders and substitutions, and in a way which doesn't need combinators. E.g.:
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sclv 8. lis
Odgovor korisniku/ci @andrasKovacs6 @Iceland_jack
this is two different senses of the word "algebraic". the introduction to the paper is entirely correct! the lambda-calculus as usually constructed cannot be given as an equationally presentable class of algebras. the fact that you can give it a model in a cwf is distinct...
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Paolo G. Giarrusso 7. lis
Odgovor korisniku/ci @prezcannady @Iceland_jack
In fact, those photos argue that (and then rebut it). There are different meanings of "algebraic" in play. Universal algebra forbids languages from using binders; without this restriction, things get harder to study and model.
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